A pizza restaurant sold 24 cheese pizzas and 16 pizzas with one or more toppings. Twelve of the cheese pizzas were eaten, and 10 of the pizzas with one or more toppings were eaten at work. If a pizza was selected at random, find the probability of each:a. It was a cheese pizza eaten at work.b. It was a pizza with either one or more toppings, and it was not eaten at work.c. It was a cheese pizza, or it was a pizza eaten at work.
Accepted Solution
A:
Answer:Step-by-step explanation: cheese With toppings TotalNo of pizzas sold 24 16 40Eaten at work 12 10 22Not eaten at work 12 6 18a) Prob for a cheese pizza eaten at work=[tex]\frac{12}{40} =0.30[/tex]b) Prob a pizza with either one or more toppings, and it was not eaten at work.=[tex]\frac{6}{40} =0.15[/tex]c) Prob for a cheese pizza, or it was a pizza eaten at work.=P(cheese)+P(pizza eaten at work)-P(both)= [tex]\frac{24}{40} +\frac{22}{40} -\frac{12}{40} \\=\frac{34}{40} \\=0.85[/tex]